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LinkedListCycle.java
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69 lines (56 loc) · 2.47 KB
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/**
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* This code snippet is copyright at qmz.com.au
* - qmz.com.au is a top-ranking IT consulting firm that specialised in
* - Mobile Development, Web Development, Machine Learning, and Cloud Computing.
* - We provide individual and company training for professional development.
* - Find out more information in our official site:
* - https://qmz.com.au
*/
// Given a linked list, determine if it has a cycle in it.
// To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If pos is -1, then there is no cycle in the linked list.
// Example 1:
// Input: head = [3,2,0,-4], pos = 1
// Output: true
// Explanation: There is a cycle in the linked list, where tail connects to the second node.
// Example 2:
// Input: head = [1,2], pos = 0
// Output: true
// Explanation: There is a cycle in the linked list, where tail connects to the first node.
// Example 3:
// Input: head = [1], pos = -1
// Output: false
// Explanation: There is no cycle in the linked list.
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if (head == null || head.next == null) { return false; }
ListNode slow = head, fast = head.next;
while (fast != null) {
if (slow == fast) { return true; }
slow = slow.next;
if (fast.next != null) {
fast = fast.next.next;
} else {
return false;
}
}
return fast == null ? false : true;
}
}