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53_maximum_subarray.cpp
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66 lines (54 loc) · 1.35 KB
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#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int maxSum = nums[0], currSum = 0;
for (int i = 0; i < nums.size(); ++i) {
currSum += nums[i];
maxSum = max(maxSum, currSum);
if (currSum < 0) {
currSum = 0;
}
}
return maxSum;
}
};
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
vector<int> nums = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
Solution solution;
int result = solve.maxSubArray(nums);
cout << result << '\n';
return 0;
}
/*
------------------
Problem Statement:
------------------
Given an integer array nums, find the subarray with the largest sum, and return its sum.
----------
Example 1:
----------
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.
----------
Example 2:
----------
Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.
----------
Example 3:
----------
Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.
------------
Constraints:
------------
1 <= nums.length <= 10^5
-10^4 <= nums[i] <= 10^4
*/