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LonelyInteger.java
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75 lines (59 loc) · 2.04 KB
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/*Problem Statement: Lonely Integer
Given an array of integers, where all elements but one occur twice, find the element that occurs only once.
Function Description:
Complete the lonelyInteger function in the editor below.
lonelyInteger has the following parameter:
List<Integer> a: an array of integers
Returns:
int: the element that occurs only once
Input Format:
The first line contains a single integer, n, the number of integers in the array.
The second line contains n space-separated integers that represent the array a.
*/
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
class Result
{
/*
* Complete the 'lonelyinteger' function below.
*
* The function is expected to return an INTEGER.
* The function accepts INTEGER_ARRAY a as parameter.
*/
public static int lonelyinteger(List<Integer> a)
{
// Write your code here
int arrayElementsSum = 0;
for(int n : a)
{
arrayElementsSum ^= n;
}
return arrayElementsSum;
}
}
public class LonelyInteger
{
public static void main(String[] args) throws IOException
{
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int n = Integer.parseInt(bufferedReader.readLine().trim());
List<Integer> a = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
.map(Integer::parseInt)
.collect(toList());
int result = Result.lonelyinteger(a);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedReader.close();
bufferedWriter.close();
}
}