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InorderTraversal.java
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90 lines (74 loc) · 2.04 KB
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/*Problem Statement: Inorder Traversal of a Binary Tree
Objective
Given the root node of a binary tree, you need to print the values of the nodes in inorder traversal as a single line of space-separated values.
Inorder Traversal
Inorder traversal is a depth-first traversal method where nodes are visited in the following order:
Left Subtree: Visit all nodes in the left subtree.
Root Node: Visit the root node.
Right Subtree: Visit all nodes in the right subtree.
Input
root: A Node object representing the root of the binary tree.
Output
Print the values of the nodes in inorder traversal in a single line of space-separated values.
Constraints
The tree will contain unique integer values.
The binary tree is not necessarily balanced.
*/
import java.util.*;
import java.io.*;
class Node {
Node left;
Node right;
int data;
Node(int data) {
this.data = data;
left = null;
right = null;
}
}
class InorderTraversal {
/* you only have to complete the function given below.
Node is defined as
class Node {
int data;
Node left;
Node right;
}
*/
public static void inOrder(Node root)
{
if(root == null)
{
return;
}
inOrder(root.left);
System.out.print(root.data + " ");
inOrder(root.right);
}
public static Node insert(Node root, int data) {
if(root == null) {
return new Node(data);
} else {
Node cur;
if(data <= root.data) {
cur = insert(root.left, data);
root.left = cur;
} else {
cur = insert(root.right, data);
root.right = cur;
}
return root;
}
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int t = scan.nextInt();
Node root = null;
while(t-- > 0) {
int data = scan.nextInt();
root = insert(root, data);
}
scan.close();
inOrder(root);
}
}